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-5t^2+9t+7=0
a = -5; b = 9; c = +7;
Δ = b2-4ac
Δ = 92-4·(-5)·7
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{221}}{2*-5}=\frac{-9-\sqrt{221}}{-10} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{221}}{2*-5}=\frac{-9+\sqrt{221}}{-10} $
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